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Oct 30, 2015 at 23:31 vote accept Systemsfailed
Oct 30, 2015 at 20:10 comment added Engineer See edit, my original answer was far from complete.
Oct 30, 2015 at 19:56 comment added wondra It is only fairly quick O(N) test (two multiplications, one addition) or just one condition if you precomputed it in 2D array... see the Arcane Engineers answer - the talk about this started there. Problem with 2D array might be the memory 4*N bytes.
Oct 30, 2015 at 19:56 comment added Engineer An octree is overkill for this, IMO.
Oct 30, 2015 at 19:50 comment added Systemsfailed So what are you suggesting, that every time I check all available jump targets in range I iterate through the entire collection of all systems to determine what's in range?
Oct 30, 2015 at 19:43 answer added Engineer timeline score: 2
Oct 30, 2015 at 19:43 comment added wondra Why would you store graph if it is 1.) complete graph with 2.) well-known edge weight(and easily computable!)? All the information is implicit given by already existing attribute(position).
Oct 30, 2015 at 18:58 review First posts
Oct 30, 2015 at 20:35
Oct 30, 2015 at 18:57 history asked Systemsfailed CC BY-SA 3.0