2
\$\begingroup\$

I am trying to do some physics calculations from scratch, and as a result am creating a small bouncing ball example. However, I have some issues getting correct results from my impact physics when the ball bounces on the floor. I have attempted to follow the simple guide on Gamasutra (as referenced by my lecturer) that does impact physics between two balls. This is elastic collisions meaning the energy should be preserved (the ball should keep bouncing). I can cheat but I do want the proper physics calculations of the impact working as I need to use this for more complicated things later.

My current problem is that the ball bounces to a much higher position than it's starting point. I.e the ball starts at a specific position, with a velocity of 0,0,0 and is being effected by gravity. When it hits the floor however, the velocity calculated is much too high, so it bounces much higher (out of the screen) than the point at where it was dropped. It should, I believe, bounce back to the starting position. Here's a small gif showing what's happening.

ball drop

Here's my current code. Could anyone point me in the right direction? Thanks!

// create sphere radius 3, color red
my_sphere = new Sphere(3, Vector(0.0,0.0,1.0) );
// set position
my_sphere->setDisplacement( Vector(0,50,0) );
// add gravity acceleration
my_sphere->addAcc( Vector(0.0, -9.82, 0.0) );

Physics foce calculation

// changes the objects velocity and position according to acceleration and time
void PhysicsObject::forceStep(float dt) {

    this->vel = this->vel + this->acc*dt;

    Vector s = this->vel*dt  + ( this->acc * (1/2.0f)  * pow(dt,2) );
    this->displacement = this->displacement + s;
}

Impact physics:

if ( my_sphere->floor_collision() ) {
        // floor properties
        Vector floor_vel = Vector(1,1,1);
        Vector floor_pos = Vector(0,0,0);
        // the floor is immovable e.g. mass=infinite 
        float floor_mass = std::numeric_limits<float>::max();
        // Ball properties
        Vector ball_vel = my_sphere->getVel();
        Vector ball_pos = my_sphere->getDisplacement();
        float ball_mass = 1;
        Vector n = ball_pos - floor_pos;
        n = n.normalize();

        float a1 = ball_vel.dotProduct(n);
        float a2 = floor_vel.dotProduct(n);

        float optimizedP = (2.0 * (a1 - a2)) / (ball_mass + floor_mass);

        Vector new_ball_vel = v1-n*optimizedP * floor_mass;

        my_sphere->setVel( new_ball_vel );
}
\$\endgroup\$
5
  • 3
    \$\begingroup\$ Your naming convention makes it hard to follow your intention: n, a1, a2 and optimizedP is unclear. \$\endgroup\$ Commented Feb 7, 2015 at 18:38
  • 1
    \$\begingroup\$ Hmm.. It appears you set the floor's velocity to (1, 1, 1) ? The floor isn't moving afait. Another issue, is that you are using <float>::max() for the floor's mass which is fine theoretically (you want infinite mass) but in practice, using very large numbers in computations could get highly inaccurate results. I would test with something like ball mass 0.01 and floor mass 1,000,000. \$\endgroup\$
    – AturSams
    Commented Feb 7, 2015 at 18:58
  • \$\begingroup\$ @Zehelvion Whoops, the floor velocity was just me messing around, it doesn't change things much. Likewise changing the masses, not much change I am afraid. \$\endgroup\$
    – Jacob
    Commented Feb 7, 2015 at 20:02
  • 2
    \$\begingroup\$ @AzaraT What is v1? \$\endgroup\$
    – AturSams
    Commented Feb 7, 2015 at 20:05
  • \$\begingroup\$ Ha! Good catch. That was indeed the issue. Bad variable naming from me, it was declared in another part of the program, but was supposed to be the old velocity of the ball (in the tutorial they called that v1). Thanks! \$\endgroup\$
    – Jacob
    Commented Feb 7, 2015 at 20:10

1 Answer 1

1
\$\begingroup\$

@AzaraT What is v1? – zehelvion Feb 7 '15 at 20:05

 

Ha! Good catch. That was indeed the issue. Bad variable naming from me, it was declared in another part of the program, but was supposed to be the old velocity of the ball (in the tutorial they called that v1). Thanks! – AzaraT Feb 7 '15 at 20:10

\$\endgroup\$
2
  • \$\begingroup\$ You should suggest to the user to answer his own question ;) \$\endgroup\$
    – Vaillancourt
    Commented Mar 5, 2016 at 6:36
  • \$\begingroup\$ Sorry about that, accepted this one! \$\endgroup\$
    – Jacob
    Commented Mar 7, 2016 at 8:58

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .