Im trying to get a directional vector from an euler angle. But im not getting how to do it. This is what i got so far.

escapeAngle += 90;
var radians = escapeAngle * (Mathf.PI / 180);

var escapeAngleAsDirectionVector = new Vector2 ();
escapeAngleAsDirectionVector.x = Mathf.Cos (radians);
escapeAngleAsDirectionVector.y = Mathf.Sin (radians);

escapeAngleAsDirectionVector = transform.TransformPoint (escapeAngleAsDirectionVector);
  • 1
    \$\begingroup\$ What do you get? What did you expect to get? \$\endgroup\$
    – occulus
    Apr 16, 2014 at 13:52
  • \$\begingroup\$ I dont know what to expect more than a vector2 that Points in the direction of the angle. What i get is direction vector pointing in weird angles that is not the angle i provided. \$\endgroup\$
    – Daarwin
    Apr 16, 2014 at 14:59
  • \$\begingroup\$ Then edit your question and put that in your question please! \$\endgroup\$
    – occulus
    Apr 16, 2014 at 15:16
  • \$\begingroup\$ Can you give a few examples of what you're putting in and what you are getting as a result? First, you are adding 90 degrees so you are supposed to get a perpendicular vector of course. \$\endgroup\$
    – AturSams
    Apr 17, 2014 at 4:19
  • \$\begingroup\$ First thing is you shouldn't be adding 90 to the angle, unless you want a perpendicular vector rather than one facing in the same direction. \$\endgroup\$ Apr 17, 2014 at 13:06

2 Answers 2


You can create a rotation quaternion from your Euler angles. By multiplying it with a vector 'right', you get a Vector2:

Vector2 v = Quaternion.Euler(x, y, z) * Vector2.right
  • \$\begingroup\$ also most probably, z = watever, like 0, should yield the same results. you need only 2 angles for a direction. \$\endgroup\$
    – v.oddou
    Oct 15, 2014 at 1:55

The correct formula is V = {r*cos(theta), y*sin(theta)} to get a vector from an angle with line at angle theta of length r, so your calculations look right. BUT one thing you need to account for is if the angle is negative. then you would have to add 360 to the angle.


if(esacapeAngle < 0)
    escapeAngle += 360;

Another thing you should probably check if the angle is greater than or equal to 360 after the addition, because that wouldn't be valid either.

if(escapeAngle >= 360)
    throw error

then do the rest of your calculations.

This will give you a perpendicular vector though, as you add 90 to the angle.

Converting Polar coordinates to Cartesian coordinates


You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .