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I want to fire an arrow toward the mouse location.
X0 = the players X location
X1 = the mouse X location
Y0 = the players Y location
Y1 = the mouse Y location
I want to make a method which takes degrees as a parameter, and sets the Yspeed and Xspeed accordingly, so the arrow can reach the mouse position, starting at the player position.
I am using float coordinates (i.e. float x, y, z).
How can I do this?
This " answer " is to add some visual information to the answers already given.
2: We first create a vector ( 2D in this case with component x and y ) by taking the difference from both positions ( mouse - player ).
3: We then Normalize it to create a so called " unit vector ". Which means to bring the length of our vector to 1. This is done by dividing both x and y component of the vector by the length/magnitude. We need this because this is our direction vector. It simply tells in which direction we are heading for the x and y axis.
4: Now we have the direction we just need to multiply it by a scalar ( or simply put by your speed). Since the length is 1. Any number we multiply with will result in a new vector with the length equal to your given speed. Just remember that a unit vector represents the direction of your vector. Basically the red dotted lines is how much it moves in the x direction and how much it moves in the y direction per frame.
So recap:
Unit vector = direction
Magnitude/Length/speed = steps to move per frame on x and y axis.
(The lengths in the drawing are just for visual aid, they are not meant to be accurate )
Hope this helps.
(v_x^2+v_y^2+v_z^2-v_b^2)t^2 + 2*(v_x*c_1+v_y*c_2+v_z*c_3)t + (c_1^2+c_2^2+c_3^2) = 0 mean. That is until I found this properly dissected and explained answer. Have my +1, you deserve every byte (<- being literal) of it! =D
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Jun 18, 2013 at 0:41
You are trying to fire an arrow from point a(player) to b(mouse position) in 2d space?
you can simply do the following formula to get the direction. (rather than degree)
v1 = ( Player.x, Player.y );
v2 = ( Mouse.x, Mouse.y );
dir = v2 - v1;
dir.normalize();
arrow.xy += dir * speed;
hope this helps you achive what you want.
The ratio of the horizontal to the vertical component of the vector is proportional to the ratio of the horizontal and vertical difference in position. The proportion factor is the speed divide by the direct distance (calculated by the pythagorean theorem).
distance.x = target.x - start.x;
distance.y = target.y - start.y;
distance_direct = square_root((distance.x * distance.x) + (distance.y * distance.y)); // pythagoras
vector.x = distance.x * (speed / distance_direct);
vector.y = distance.y * (speed / distance_direct);
Note that this will result in a division by zero when the distance is zero (start and target position are identical). That makes sense, because in that case the vector is undefined (in what direction do you not-go when you want to stay where you are?). This case needs to be handled separately.
Note that there is no reason to use degree here. When you have an angle in degree and a speed, you can convert it to x and y direction using sine and cosine:
vector.x = sin(angle) * speed
vector.y = cos(angle) * speed
In most programming languages, the sine and cosine functions use radiants, not degrees. That means a full 360° circle is 2*PI (approximately 6.283185) you can convert degree to radiants by multiplying them with PI / 180 or approximately 0.01745329.
{dx,dy}pair. \$\endgroup\$