I have a 2D map, for each element I apply this isometric projection to place my Sprite

 //Element e;
float[] f= projection(e.getX(), e.getY() ,z);
// x and y represent Sprite Coordonate (tile_width and height depend of my
// camera size and the number of elements in x and in y
float x =  f[0]*tile_width;
float y =  f[1]*tile_height;


   public float[] projection(float x, float y, float z)
{
return new float[]{  (( x )-(y) ) , ((x/2) + (y/2) - z  )};
}


the sprite for one element :

The result of my projection :

The problem is I need to add an offset of tile_height/2 to the y and tile_width/2 to the x to have something like this (in the red rectangle I drawed with paint what I want) :

Where did I make wrong?

(I found the projection method in How should I sort images in an isometric game so that they appear in the correct order? )

edit : How I calculate my tile_height and tile_width :

    tile_height = (float) ((CAMERA_HEIGHT/(game.map.getHeight()/2)));
tile_width =  (float) ((CAMERA_HEIGHT/(game.map.getWidth()/2)));

• I haven't done isometric projection before, but shouldn't the tile_height and tile_width be the height and width of the tile sprite? – tugs Nov 21 '12 at 22:13

I am not sure how to create a single projection for multiplying with width and height, but I believe if you send the height and width along, the Projection would be:

public float[] projection(float x, float y, float z, float width, float height)
{
return new float[]{
(x * width / 2) + (y * width / 2),
(y * height / 2) - (x * height / 2) - (z*height)
};
}


Maybe have a look at 1ManBandStudios' post here.

I hope this helps :)

• I notice an interesting difference in the calculations here. Your code calculates the projection as [x+y, y-x-z] where the code in the question uses [x-y, x+y-z] – tugs Nov 20 '12 at 23:05
• That doesn't matter - it just changes the orientation (which direction is x/y). – Mario Nov 21 '12 at 0:55
• It doesn't work – Christophe Debove Nov 21 '12 at 8:17