Getting closest distance between a square's edge and a point 2D

Question

How would I get the closest distance between a square's edge and a point in 2D, if I only have the points coordinates, and the coordinates of the square and it's size?

Answer 1

float DistanceFromRectangle(Vector2 point, Vector2 center, Vector2 size, float angle) {

    // First, transform the point into the rectangle's local coordinate space.
    Vector2 offset = Rotate(point - center, -1 * angle);

    // Take the absolute value of this offset, on x and y, and subtract the size.
    // This gives zero on the edge, increasing positively as we move away.
    // Clamp out any values less than zero.
    Vector2 outside = Max(Abs(offset) - size/2, Vector2.zero);

    // Return the length of this vector, which is our distance to the closest point
    // on the square's edges or corners, and zero inside the square.
    return Length(outside);
}

Answer 2

Thank you Felsir and DMGregory, I just googled 'distance point to square' and I found a already existing stackexchange question about this. How do I calculate distance between a point and an axis-aligned rectangle? Thanks!!