1
\$\begingroup\$

I'm trying to make a camera system where the camera never goes outside the edges of the current room (like Link to the Past or Mega Man, for example)

This is what I have right now:

using UnityEngine;
using System.Collections;
public class CameraFollow : MonoBehaviour {
public BoxCollider roomBounds;
public Player target;
Vector3 velocity;
float halfHeight,halfWidth;
void Start(){
    halfHeight = Camera.main.orthographicSize;
    halfWidth = halfHeight * Camera.main.aspect;
}
void LateUpdate(){
    Vector3 targetPosition = target.transform.position;
    if (targetPosition.x+halfWidth >= roomBounds.bounds.max.x || targetPosition.x-halfWidth <= roomBounds.bounds.min.x) {
        velocity.x = 0;
    } else {
        velocity.x = targetPosition.x - transform.position.x;
    }
    if (targetPosition.y+halfHeight >= roomBounds.bounds.max.y || targetPosition.y-halfHeight <= roomBounds.bounds.min.y) {
        velocity.y = 0;
    } else {
        velocity.y = targetPosition.y - transform.position.y;
    }
    transform.position += velocity;
}
}

It works on a rudimentary level, but the problem is, whenever you're moving out from a wall after the camera's stopped, it snaps a little to the left or the right, and then goes back. Same vertically.

Any idea as to what might be causing this and how to solve it?

P.S. I know there have been a lot of threads about this kind of system (even one 21 hours ago), but none I've found helped me much.

\$\endgroup\$
1
\$\begingroup\$

Clamping the Camera's position at the end of position calculation would fix your problem. Put this code at the end of your ''LateUpdate()'' method.

float finalXPos = Mathf.Clamp(transform. Position.x, roomBounds.bounds.min.x + halfWidth, roomBounds.bounds.max.x - halfWidth);
float finalYPos; // Do the same calculation for Y position.
transform.position = new Vector2(finalXPos, finalYPos);

Note: Code might be little of syntactically (since I cannot test it right now), and also there might be a clamping function for Vector2, which you can search for it.

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.