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i like to be able to calculate the vector values from object A to destination position. For Example in this image object A to destination B . What will be the x/y positions all the way until it reach distention B. where the x,y origin is in bottom left side enter image description here

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  • \$\begingroup\$ Isn't a subtraction of A from B sufficient (Diff = B - A)? Also, the amount of positions between A and B is infinite. What exactly are you trying to do? \$\endgroup\$ – Alexandre Vaillancourt Jun 3 '17 at 13:12
  • \$\begingroup\$ to calculate the movement from A to B \$\endgroup\$ – user3689 Jun 3 '17 at 14:20
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    \$\begingroup\$ That's not enough information to give an answer... If you want to move 10% of the distance just scale the vector by 10%. I feel like this question lacks research effort. \$\endgroup\$ – Charanor Jun 3 '17 at 16:02
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If you just want the the vector from 'A' to 'B' thats 'C = TargetPos - StartPos = B - A', no matter how they are orientated.

If you want a function to return a position on this line between, that's 'pos(x) = StartPos + (TargetPos - StartPos) * x = A + C * x', where either x is a number between 0 ( lower you would have a point further away from B) or 1 (higher means you went through B and got further).

Most of the time your 'C' gets normalized, so still points in the same direction, but has 'length = 1', so C_n = C / Length of C. . In that case x should be between 0 and 'Lenght of C'.

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