i'm trying to print a string letter by letter for UI Text of Unity. With each click of a button, the Stampa function, must print a letter. Up to this point everything is working perfectly. But if I try to print a newline "\n" the function ignores him and continues to print on the same line.
This is my code:

using UnityEngine;
using UnityEngine.UI;

public class Click : MonoBehaviour {

    public static Text txt;
    public static int indice = 0;
    public string asd = "String1 \nStriga2";

    void Awake() {
        txt = GameObject.Find("Cmd").GetComponentInChildren<Text>();

    public void Clicked() {
        Stampa(asd ,indice);

    void Stampa(string stringa, int i) {
        txt.text += stringa[i];


That produces this result(unwanted): enter image description here

I also tried to print the entire string at the same time (not a letter at a time) as follows:

txt.text = "String1 \nStriga2";

That produces this result(wanted): enter image description here
How can I get this second result by printing letter by letter?

  • 1
    \$\begingroup\$ Check if string[i] is a slash, if it is then add both i and i+1 \$\endgroup\$ – DH. Jul 18 '16 at 18:01

It's reading one character at a time, so it's not properly escaping the new line. I would suggest looking for escape characters in your Stampa() function, and if it's an escape character, read the next character in at the same time. Something like:

void Stampa(string stringa, int i) {
    string r = stringa[i];
    if (r == '\\')
       r += stringa[i+1];
    txt.text += r;

Thought you'd likely need to return the index value to the calling function. You could return an int and maybe do something like this:

public void Clicked() {
        int val = Stampa(asd, indice);
        indice += val;

int Stampa(string stringa, int i) {
        int ret = 1;
        string s = stringa[i];
        if (s == '\\')
           s += stringa[i+1];
        txt.text += s;

        return ret;
| improve this answer | |
  • 1
    \$\begingroup\$ Nice solution, I have not assessed the fact that he read '\n' separately. \$\endgroup\$ – Amarildo Jul 18 '16 at 19:30
  • \$\begingroup\$ It's an easy miss since dealing with larger strings it's basically read in as a single character. I'm glad it helped! \$\endgroup\$ – Jesse Williams Jul 18 '16 at 19:39
  • \$\begingroup\$ @Amarildo, I accepted your change from string to char, then reverted the change back because the value of s can be more than one character - that was the whole point of the added code, to allow string s = "\\nS" or something similar, right? Two character, the newline and the next character in from your asd value. \$\endgroup\$ – Jesse Williams Jul 18 '16 at 19:46

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