I've been struggling with a problem regarding rotations and relative positions between sprites (in this case, the sprites are just lines) - a bit off-topic, but should i be using the ShapeRenderer class to do this, though?

Anyway, it might be quite simple but i can't seem to figure it out properly. Heres a picture of the situation: https://gyazo.com/78988e07991fedc778eaeb70f8a04d8e

Now, after trying a bunch of different approaches, this piece of code is the one i'm testing right now:

` public class TestState extends AbstractGameState {

private static final String LINE = "lineEffect.png";

private Sprite[] sprites;

public TestState(GameStateManager gsm) {

    sprites = new Sprite[2];
    for (int i = 0; i < 2; i++) {
        sprites[i] = new Sprite(new Texture(LINE));
        // both lines starting at the same X and Y
        sprites[i].setPosition(20, 50);
        // both lines have the same size
        sprites[i].setSize(100, 2);
        // guess i might be messing up here
        sprites[i].setOrigin(sprites[i].getX(), sprites[i].getY());

    // for testing purposes

public void render(SpriteBatch batch) {
    for (Sprite sprite : sprites)

Any help on this would be appreciated, thanks in advance.

  • \$\begingroup\$ Returns the function "sprites[x].getX()" its corner X coordinate? If not, the origin should be set on it's corner point to get the correct rotation; \$\endgroup\$ – Ahmet Zambak Nov 19 '15 at 23:55
  • \$\begingroup\$ @AhmetZambak i'm not sure if that's what you're asking, but sprites[x].getX() returns 20, wich is the X value i applied in the line before. I thought that, by starting there, the X value wouldn't be moddified, just the sprite's rotation. \$\endgroup\$ – Francisco Nov 20 '15 at 13:14

You should set the origin to a line edge:

// guess i might be messing up here
sprites[i].setOrigin(0, 0);

It depends on real line location in lineEffect.png.

  • \$\begingroup\$ thank you for the answer! Setting the origin to (0,0) was the solution. Thanks you very much! :) \$\endgroup\$ – Francisco Nov 24 '15 at 21:08

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.