0
\$\begingroup\$

Have a question on keyboard inputs. Currently I am using this method to read my input, Gdx.input.isKeyPressed(Input.Keys.A), it is working fine. But I do realized at times there are multiple instances of A being pressed when I only press once. And I understand that the method had to be placed in the render() method for it to work. Is the problem due to the refreshing?

My question is, how can I only detect 1 instance of "A", when A is pressed for once.

\$\endgroup\$
2
  • \$\begingroup\$ Maybe I should clarify myself, when i detected the key then the textfield will be updated with the input. \$\endgroup\$
    – leDon
    Commented Oct 1, 2013 at 14:49
  • \$\begingroup\$ Eh, I think i got what you mean, Thanks for the help :) \$\endgroup\$
    – leDon
    Commented Oct 1, 2013 at 14:59

2 Answers 2

1
\$\begingroup\$

LibGdx library provided an InputProcessor Interface, I think you are better to implement the InputProcessor and you should set Screen's input processor to the class you made, see tutorials that dermetfan user made on youtube http://www.youtube.com/user/dermetfan/videos

however you may would like to use different methods, also check DeviceInfo of LibGdx for checking devices.

\$\endgroup\$
-1
\$\begingroup\$

store the current keys state, get the new ones and

if(newInput.isKeyPressed(Input.Keys.A) && oldInput.isKeyUp(Input.Keys.A))
\$\endgroup\$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .