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 2 added 67 characters in body edited Mar 28 '15 at 15:20 Robert Eastwood 7922 bronze badges If you are trying to deduce difference in force and how it effects a single object with a change to its center of gravity, making each component of that object, a single object and then using its force to calculate any strain or pressure would seem to be the way to do it. If you have two weights on a bar, and they rotate around the center, and then you want to change that center point of rotation, it would seem that calculating different centrifugal forces for the two different masses moving(the weights) in now different circles(different center of gravity), would give you the pressure on there connecting point the bar. The torque at a center of a car, is equal to the opposite forces applied from the front and back of the car. the spinning and sticking out your arm is the ice skater question, you would slow down since some of the mass is traveling a greater distance, or something like that. But to calculate it, make your arm a separate object that then applies the force through the rigid connection. The force your arm would be applying would be its inertial force. If you are trying to deduce difference in force and how it effects a single object with a change to its center of gravity, making each component of that object, a single object and then using its force to calculate any strain or pressure would seem to be the way to do it. If you have two weights on a bar, and they rotate around the center, and then you want to change that center point of rotation, it would seem that calculating different centrifugal forces for the two different masses moving(the weights) in now different circles(different center of gravity), would give you the pressure on there connecting point the bar. The torque at a center of a car, is equal to the opposite forces applied from the front and back of the car. the spinning and sticking out your arm is the ice skater question, you would slow down since some of the mass is traveling a greater distance, or something like that. But to calculate it, make your arm a separate object that then applies the force through the rigid connection. If you are trying to deduce difference in force and how it effects a single object with a change to its center of gravity, making each component of that object, a single object and then using its force to calculate any strain or pressure would seem to be the way to do it. If you have two weights on a bar, and they rotate around the center, and then you want to change that center point of rotation, it would seem that calculating different centrifugal forces for the two different masses moving(the weights) in now different circles(different center of gravity), would give you the pressure on there connecting point the bar. The torque at a center of a car, is equal to the opposite forces applied from the front and back of the car. the spinning and sticking out your arm is the ice skater question, you would slow down since some of the mass is traveling a greater distance, or something like that. But to calculate it, make your arm a separate object that then applies the force through the rigid connection. The force your arm would be applying would be its inertial force. 1 answered Mar 28 '15 at 15:13 Robert Eastwood 7922 bronze badges If you are trying to deduce difference in force and how it effects a single object with a change to its center of gravity, making each component of that object, a single object and then using its force to calculate any strain or pressure would seem to be the way to do it. If you have two weights on a bar, and they rotate around the center, and then you want to change that center point of rotation, it would seem that calculating different centrifugal forces for the two different masses moving(the weights) in now different circles(different center of gravity), would give you the pressure on there connecting point the bar. The torque at a center of a car, is equal to the opposite forces applied from the front and back of the car. the spinning and sticking out your arm is the ice skater question, you would slow down since some of the mass is traveling a greater distance, or something like that. But to calculate it, make your arm a separate object that then applies the force through the rigid connection.