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Just in case anyone is interested: Lets assume sqrt(3) is rational: Therefore, there must be two integral numbers a and b such that a/b = sqrt(3) We assume these numbers are coprime, if they have a common factor, we divide by it producing a coprime pair, a and b We know that (a/b)^2 = 3 and therefore a^2 = 3 * b^2. 3 * b^2 is devisible by 3 as b^2 is ...



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