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Your top code chunk is: t2 * (t1 * direction * inverse(t1)) * inverse(t2) Your bottom chunk is: t3 * direction * inverse(t3) Given that t3 = t2 * t1 It's (t2 * t1) * direction * inverse(t2 * t1) As far as my knowledge of Quaternion multiplication goes, I don't think t2 * (t1 * direction * inverse(t1)) * inverse(t2) and (t2 * t1) * direction * ...



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