Game Development Stack Exchange is a question and answer site for professional and independent game developers. Join them; it only takes a minute:

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

I'm not so familiar with 3D modelling, and I'm stuck on a simple task in Blender.

I have a fairly complex model that's been imported as a .DAE file from SketchUp. This model is composed of many polygons, not as one single mesh but in many components, in fact over many hundreds of surfaces.

As I said I'm new to Blender and want to learn. If I select one of the component surfaces, I can go into Edit mode and then use the Decimate modifier to reduce the poly-count.

But it doesn't want to let me do this if I select the whole object!

I think I need to combine all the surfaces into one mesh (?) and then apply the Decimate algorithm to gracefully reduce the poly-count.

I've managed to do this before but unfortunately I forgot how and I need to try again to get the balance right on the poly-count.

Appreciate the help.


share|improve this question
up vote 1 down vote accepted
  1. select 2 or more "components" (in Blender terms, these are separate objects) ([B] will box-select, may be easier than shift-clicking through all the objects)
  2. [Ctrl] [J] "Join"

I haven't used Blender in a long time. What helped me learn some commands was remembering the name of the command. If you bring up the spacebar menu and type in "Join", it will bring back a list of all the commands containing that word, including their keyboard shortcuts.

share|improve this answer

I figured it out by just selecting the biggest objects and decimating them one at a time, rather than trying to do the whole object, although you'd think that would be possible.

I tried all the vertex/edge/face merging tools and none of them seemed to do anything, still need to figure that one.

share|improve this answer

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.