I have a tile based game that is in a semi-isometric view created by a transformation. The tiles are created by a Texture2d rendered on a 3d surface.
Map Image: http://balancedcms.com/Capture.PNG
I am using the following code for transformation:
View = Matrix.CreateLookAt(new Vector3(0, -1.1f, 1.6f), new Vector3(0, 0, 0), new Vector3(0, 53, 0)); Projection = Matrix.CreatePerspectiveFieldOfView(MathHelper.Pi - 2.4f, 4.0f / 3.0f, 1, 500); quadEffect = new BasicEffect(device); quadEffect.World = Matrix.Identity; quadEffect.View = View; quadEffect.Projection = Projection; quadEffect.TextureEnabled = true; quad = new Quad(new Vector3(0, 0, 0), Vector3.Backward, Vector3.Up, 3, 3);
My problem comes along when I attempt to get the current tile that I am hovering the mouse over. I have a mouse X and Y however I can't seem to figure out how to transform these screen coordinates into a tile X and Y. The tiles are 128px by 128px; however, after the camera transformation they are smaller on the top and larger on the bottom(to create the isometric view)
I've tried transforming the mouse X and Y with the same projection matrix. However, this didn't work. I think it is due to the view matrix not being taken into account... sample below:
Vector3.Transform(new Vector3(Mouse.GetState().X, Mouse.GetState().Y, 0), Projection);
This image may provide more information... is also shows the hours I've put into figuring this out: http://balancedcms.com/1111.png